How to generate Level Codes in Revit with PropertyWizard

It’s useful if your Revit Levels have a Level Code as well as a Level Name. That way, you can use the Level Code in your formulas for door numbers, room numbers, etc:

Level NameLevel Code
Level 000
Level 101
Level 202
Level Names and Level Codes

You could type the level codes in, level by level. But if you have PropertyWizard, you can just generate them. This post walks through a couple of different ways of generating the level codes from the level names. And on the way, it explains two of the text functions in PropertyWizard: substr() and strlen().

Method 1: Simple substr()

The substr() function extracts a number of characters from a text value. It has three inputs:

substr(<text value>, <start character>, <number of characters>)

The <text value> is the text you want to extract characters from. In this case it will be the value of the Level’s Name parameter.

The <start character> is the character number to start at, with the first character in the text being number 0. In these level names, the digit is character number 6.

The <number of characters> is how many characters you want to extract. In this simple case, you would use 1 to extract just one digit.

So the substr will look like this:

substr(Name, 6, 1)

Finally, to generate the full level code, you prefix the extracted digit with a “0”:

"0" + substr(Name, 6, 1)
PropetyWizard Formula Window showing simple Level Code formula using substr

Method 2: substr() with strlen()

Method 1 will work for levels up to 9, but will fail with two-digit levels, 10 and up. How can you fix that?

Since the two-digit levels are longer than the one-digit ones, you can use an if() function and a strlen() function to choose between two different options.

The strlen() function simply returns the number of characters in the input text value:

strlen(<text value>)

The if() function chooses between two alternatives. It has three inputs:

if(<test>, <output if true>, <output if false>)

The <test> is an expression that evaluates to true or false. In this case, if the level name is 7 characters long you know that it is a one-digit level. Otherwise it will be a two-digit level:

if(strlen(Name) == 7, <one-digit level>, <two-digit level>)

If it is a one-digit level, you would use the function from Method 1, but if it is a two-digit level, you would just need something like:

substr(Name, 6, 2)

So the completed formula will be something like this:

if(strlen(Name) == 7, "0" + substr(Name, 6, 1), substr(Name, 6, 2))
PropetyWizard Formula Window showing simple Level Code formula using strlen and substr